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All Numbers Are Equal
5 f# e _; U0 ~- p3 ETheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then 5 _( B; ]( P6 p3 ?
: i2 J& l4 f& _6 z) M8 {. ta + b = t
7 D: X' `. Q" i( {0 Z2 O(a + b)(a - b) = t(a - b)* U8 I3 D0 _8 a$ Y0 N6 L; T
a^2 - b^2 = ta - tb
) o/ H# g0 m$ I4 |1 m5 ua^2 - ta = b^2 - tb
7 D. y+ B2 l( O5 d0 @/ x2 l9 ya^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4: C0 v9 @2 R' J' l9 s7 s7 U
(a - t/2)^2 = (b - t/2)^2
/ N& Q3 f# J) J; y3 _, ~a - t/2 = b - t/2
' V4 U4 Y0 N% ?, C$ U, e7 da = b / G9 G: |" s8 `: i
4 f3 s" x7 ]. Q3 {+ LSo all numbers are the same, and math is pointless. |
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