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All Numbers Are Equal % o5 Z( F- \& c' T/ Y
Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then
y% h* P2 J6 x, l1 [* `' c
9 v+ I% W, \5 y# f' ?6 ja + b = t
' t* A( K0 p8 x2 b& X* s* T3 K5 l(a + b)(a - b) = t(a - b)+ W3 I: S9 \2 Z: r% ]4 j) m
a^2 - b^2 = ta - tb
, |* f* v- G' X- M' ca^2 - ta = b^2 - tb: l4 g6 y9 z9 z: u" \0 a
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
, N e& h a# a' h' ^0 V$ v5 i D/ x(a - t/2)^2 = (b - t/2)^2
- \' L, P# Z: s1 T; ?8 `0 z( Z# a0 e% Wa - t/2 = b - t/2% a- c1 d& [( F. e2 \
a = b % B# }& s$ G! S4 S$ B' Q
9 A' Q& c0 p3 uSo all numbers are the same, and math is pointless. |
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