All Numbers Are Equal

我来也

All Numbers Are Equal   
Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then
% {2 b4 V' r4 v" K' y. R
a + b = t
8 p" g0 x. U7 J1 k(a + b)(a - b) = t(a - b)
8 h3 p: z" w+ e% @9 L4 Ua^2 - b^2 = ta - tb
/ q2 d; ^9 O4 P1 V+ ~a^2 - ta = b^2 - tb
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
5 A/ E; A2 U( S7 i/ y# [& M(a - t/2)^2 = (b - t/2)^2
a - t/2 = b - t/2
a = b
* F( T: v' L& m+ e
So all numbers are the same, and math is pointless.

老V

朋友    你算错了    在检查一遍吧

我来也

原帖由 老V 于 2006-6-13 11:05 发表
1 h/ t: q' D% q. `. R朋友    你算错了    在检查一遍吧

高桥

does a^2=b^2 implies a=b? why not a=-b?

我来也

原帖由 高桥 于 2006-6-13 12:11 发表
does a^2=b^2 implies a=b? why not a=-b?

高桥

原帖由 我来也 于 2006-6-13 21:47 发表

+ H; Y1 b& J  F' i1 W5 ]