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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置
' b' a9 T" g6 h% l* ~7 D2 ]1 l$ m0 }0 p& n, ?
6 Y" {1 }: ?- q; }! Q" i# t- E4 Z1 I, p0 S" f
(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:
0 s' j) c% ^0 N1 V2 m1 p+ H: l
* C& D0 f0 Y( E: tmz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.
: k% ^% h) s* K" X2 x C' u x( x! Z b. b& U, T
Calculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).
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发表于 2012-4-2 21:27
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