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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置
$ M0 u$ z$ B" k7 c \% D4 _ U% y# w1 D$ Y( k# Q3 L
. V9 D. d& |1 l9 W$ Z% t% g6 j' a7 C0 j
(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:
, d ^" M/ T* T/ |$ Q( w2 n# b( c) v4 W
mz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.( h7 s2 ^/ B7 |4 Q* {. T
* B; F, C. q: w# K" kCalculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).. q; g2 Q! S+ _/ P, F3 x
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