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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 ! h" p. |2 v( c) S) \/ }4 [' C4 ]
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; v* Y- ~( X/ W. ^0 B! O足球看完了来看看题目。6 L6 O+ @+ G* J) t
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The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)+ B& L5 I& f7 |9 I
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
; z5 K7 g8 G0 l7 Y$ S' w' e! g3 DWe can see it is not easy to install the 22 meters heat trace according as figure 1% f% _8 u8 d: ~1 F
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$ e7 B d$ _$ q% T% n5 P2 O MAs a normal question we just discuss:- _9 ?4 P, z6 ], L8 b; _7 _
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? . e6 V3 L# ]/ W* J
I call this is JACK LAI Spiral Method 螺旋法
4 P/ f" B4 [) @The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.# @$ f0 W" E% _ ^0 _
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
; c6 \2 ^0 A/ ?1 H+ f Q( yBecause the pipe is horizontal, position 0 can not be placed. See figure 2* p1 X, Q. J8 q+ k7 y
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3/ b# g* J/ u# m# [3 ^# e( ~
The total heat trace that can be installed here is about 9 g5 K* |6 f3 }0 \
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
3 t# s# h1 w$ E/ C- H" ?So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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Note :
# C, S+ B4 B6 K1. The minimum bend radius:+ H% V. X/ L: o+ U# o& n( c+ L
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is- @7 M/ o1 ]% D& z+ N. m
5/16 *6 = 30/16 almost = 2 inches0 b" O# d2 G/ c$ p1 {" n5 c P
So the maximum bend radius is 2 inches." P4 i) q- E8 X; f8 J1 o
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As regular # A/ F0 P Z# I B) ^$ M2 f: L
For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
- z# t9 J7 [# o/ E+ L+ fif the pipe is horizontal, The length of heat trace can be installed is about! o. V' t2 Y# _" j$ p1 ?1 V
1 * 9 = 9 meters
' `3 Z @( e. c" AIf the pipe is vertical, The length of heat trace can be installed is about
+ W1 S: L' C% P. t3 @) `- s1 * 10 = 10 meters.
7 B& M; g% p, }& ~4 u5 HFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe+ l, P4 [0 V( C$ C$ D
if the pipe is horizontal , The length of heat trace can be installed is about$ U; }* C# C" g& b. u" b
1 * 4 = 4 meters
3 V5 N5 \. r! W! y) SIf the pipe is vertical, The length of heat trace can be installed is about4 @6 b# V* F2 M4 `, ^- _/ X
1 * 5 = 5 meters. |
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