All Numbers Are Equal

我来也 · 发表于 2006-6-13 09:17

All Numbers Are Equal
Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then

a + b = t
(a + b)(a - b) = t(a - b)
a^2 - b^2 = ta - tb
a^2 - ta = b^2 - tb
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
(a - t/2)^2 = (b - t/2)^2
a - t/2 = b - t/2
a = b

So all numbers are the same, and math is pointless.

老V · 发表于 2006-6-13 11:05

朋友你算错了在检查一遍吧

我来也 · 发表于 2006-6-13 11:47

原帖由老V 于 2006-6-13 11:05 发表- w& @9 A6 O. r
朋友你算错了在检查一遍吧

高桥 · 发表于 2006-6-13 12:11

does a^2=b^2 implies a=b? why not a=-b?

我来也 · 发表于 2006-6-13 21:47

原帖由高桥于 2006-6-13 12:11 发表
) g9 r2 j0 {6 F, j" |, [does a^2=b^2 implies a=b? why not a=-b?

高桥 · 发表于 2006-6-13 21:53

原帖由 我来也 于 2006-6-13 21:47 发表3 ~+ L9 ^# K6 t" w
' s/ {" o/ Y; d' o0 H3 h0 m9 M. }

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All Numbers Are Equal

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