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All Numbers Are Equal
+ Q$ b% i- M3 }, WTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then 4 V" g! U* B! w$ L% V+ K+ }4 V; K
" ]7 {" \, j0 X/ Ha + b = t
" _" W1 ^& Y4 Y0 Y(a + b)(a - b) = t(a - b)4 p; W6 l* n! D% S i
a^2 - b^2 = ta - tb
% K" d, H7 p8 U9 E$ o; oa^2 - ta = b^2 - tb
- T4 i9 p: K2 ~ S5 s T! R4 G/ Ma^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
0 W9 [9 U" A( A) K9 M2 D(a - t/2)^2 = (b - t/2)^2
& i* l* B' ~0 f6 n4 F; D! Z2 |; na - t/2 = b - t/2: D0 t1 [; u: m: X) t/ Z6 G$ G1 V
a = b 3 ~ q6 p( X! a8 A8 @+ @' P/ B
. c0 B: i+ b0 t) |! d+ d/ y
So all numbers are the same, and math is pointless. |
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