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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 ) C0 v0 H2 ]$ x# V
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/ g3 |! f1 ^% H8 ]! D# \8 d1 b6 H7 K足球看完了来看看题目。
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. S. i( x& N& [; \3 I: YThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)5 Y) P# I* ]+ o" |7 r
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
; v& F! x5 Y v2 Z0 f F" bWe can see it is not easy to install the 22 meters heat trace according as figure 1' R2 S h$ M V [5 e7 S5 x
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- ^* `- z( P7 ]( NAs a normal question we just discuss:
1 _0 Z7 ]* N5 g( @How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? % ~5 Z* D( n' O4 `! n4 c; @$ ~$ r
I call this is JACK LAI Spiral Method 螺旋法
: [2 |9 t8 A) V( k% a8 ]The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
4 c& x( Z4 v8 u$ R- nThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. & V3 F v! N* j2 |, r% A
Because the pipe is horizontal, position 0 can not be placed. See figure 2
- n3 j K: y7 B- B ` w# dBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
) p& J7 q5 T: T l' X" k S% {0 kThe total heat trace that can be installed here is about . k5 l: a8 G3 Y: Q! {1 x
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters* u% L) u$ M d8 c. V- c- D
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. 9 b3 X" `! X: t( j2 D
4 c; _) a$ E) z/ ~' ^Note :
/ L( i9 O7 E( x/ D1. The minimum bend radius:% ^7 q4 N7 p8 I- d3 s
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is+ q* w7 H, m3 |. [2 D i
5/16 *6 = 30/16 almost = 2 inches
, i7 ?, K; G2 ]3 d! LSo the maximum bend radius is 2 inches.
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As regular 9 {, l9 U7 @, i E- |
For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
6 J/ T! K; g6 A% g% S& I4 ~0 M! yif the pipe is horizontal, The length of heat trace can be installed is about. J' h" C- m' ]4 i6 m
1 * 9 = 9 meters
N( o5 H8 H7 t& h5 A% LIf the pipe is vertical, The length of heat trace can be installed is about
1 Q$ ?8 k4 V$ Y1 * 10 = 10 meters.
+ i- b( v$ H0 _For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe" D: ~8 V- h- M, p3 e5 E7 l
if the pipe is horizontal , The length of heat trace can be installed is about' d" ]9 s) X/ V% C0 Q, x* \
1 * 4 = 4 meters
9 U1 w5 {+ ~5 e+ z4 G; H% HIf the pipe is vertical, The length of heat trace can be installed is about
2 V' [3 ]9 G2 B! O% d/ W; r1 q. |% t1 * 5 = 5 meters. |
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