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All Numbers Are Equal
1 l6 v* {" I6 p1 ?0 X4 JTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then
0 n% \# ~3 _ T$ c& N% `+ q' u1 o6 R4 J- ]9 ]- m' s
a + b = t0 @5 Q/ x0 H" w$ H, O" f* z
(a + b)(a - b) = t(a - b)
1 k# z# L3 ]) j: sa^2 - b^2 = ta - tb
h$ }) ^$ a2 L# r' @& `5 |$ Ba^2 - ta = b^2 - tb1 K0 [) D2 @0 J2 H, Y& W1 p
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4/ Q, n" w+ L/ C, _9 R3 y
(a - t/2)^2 = (b - t/2)^2
' T- q: ^3 b/ ~1 |2 c" q) s, P+ Ha - t/2 = b - t/2
. v w( q1 b: R" a. U* d% I3 g# Fa = b & I7 x3 k+ z$ ?7 j) Z6 H
& s4 o- w& p7 |! I+ I, GSo all numbers are the same, and math is pointless. |
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