All Numbers Are Equal 0 f3 Z7 z) b/ {6 KTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then * o1 V4 @; N5 H0 f& V1 N/ v' t! k d6 U
a + b = t9 X" B/ E$ m2 R3 G) {* o
(a + b)(a - b) = t(a - b) / J. Z6 e; E( l4 Y6 ^3 Ha^2 - b^2 = ta - tb ! Q1 d. F }8 y! G6 ^* ?a^2 - ta = b^2 - tb( G# e, S# ? g5 v5 s8 ^
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/44 u6 Y! i7 r: m8 m1 Y+ ?+ y
(a - t/2)^2 = (b - t/2)^2& p1 e4 x( z4 R9 \7 }" z( w
a - t/2 = b - t/2 ) a5 E6 B t3 Z% g+ m' w Fa = b 8 G0 [6 P& ~9 h7 j1 _( J) ^6 i! ~2 f1 F& a6 I" g! i
So all numbers are the same, and math is pointless.