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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置
* m, O3 b [8 x) j$ n! R- J1 e8 |, r2 D2 v( D) a
+ a* f5 Q( F6 \/ g8 L6 t
) j: T+ }+ j, g6 D" g- l: ^
(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:5 F- V) @+ U- l% q' Q7 I
3 t5 N3 t, p7 l8 A9 u5 ]mz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.
$ T% t0 S8 m' b6 }7 M# t; V
! q( M1 k( ?, YCalculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).$ K$ v( E( L( V: D
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