求助一到地球物理的题

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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置
' m8 `3 O' V' @9 r5 o; U8 ~
# _+ s" y, [) t$ Y

(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:
1 `, }! f+ |- ?+ y1 \6 C
' c# n0 c% M, n" J- X& i# a' [mz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.

Calculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).
, c* a# m* S( \0 N$ g) [/ |3 n+ M3 u