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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置
{) E4 b3 p! E+ x0 s/ C7 ?, O8 C5 C+ G7 H7 V4 M4 K3 D) R
) ^; ]" X( Q( ]0 M! C: u; Y6 \
+ W' R, t2 [0 U) C4 i: \3 j) }( W
(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:
0 y- a! ]! m6 I: R4 i" o/ Y4 Q1 R
mz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.
, C1 ]1 [- m$ ~( R: l! t& y
6 z$ d8 {( L; Y, g" lCalculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).
_- ~0 p6 |! R! q" Y |
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