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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 3 D9 Y& N" A( U; f) ^
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足球看完了来看看题目。, M" t+ g/ n V" `, b5 z
; f$ f) c' m% y6 H& oThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)' y, \. n. ^9 P/ K( P0 t9 F
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)+ V! R9 q' \5 R7 E" C: k) c
We can see it is not easy to install the 22 meters heat trace according as figure 1: l5 c- }) |7 {3 H/ X! ^
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As a normal question we just discuss:6 f9 S z9 ~0 y- e+ g% s# E
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? 0 t X! J1 n d7 I
I call this is JACK LAI Spiral Method 螺旋法0 N# V3 Z* v# [* y5 t. A
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
$ A0 E( g5 F6 gThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
9 M4 ^9 W$ R X3 x; XBecause the pipe is horizontal, position 0 can not be placed. See figure 2
1 Y, d% b) q7 O7 g5 _- x6 PBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
- U/ O/ V' [0 t0 r" H5 MThe total heat trace that can be installed here is about ) ]8 z2 M3 ]0 H( x: i# n* a
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters8 b2 j/ F q* K" ]; H& C7 C+ `
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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; G H: ^" Z0 v% Y4 s1 bNote :" k4 q7 j& a) V: ^3 Y7 B
1. The minimum bend radius:
. Z* }' Q2 f, b pBecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is5 ^+ O0 R: h& G8 ?2 L
5/16 *6 = 30/16 almost = 2 inches; i1 g% A( ~- k/ u. E7 _
So the maximum bend radius is 2 inches.$ \6 a. d7 a; Z# b, c
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Summary4 H+ r6 ^1 c( }) ~, u& U0 S
As regular
5 |0 b0 ~ C5 O+ d, f* i4 NFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe& \+ W9 b: K( a6 E" \$ {( J
if the pipe is horizontal, The length of heat trace can be installed is about1 q$ S8 l7 z7 ]2 {7 \
1 * 9 = 9 meters% j p3 o( [8 x1 f! }; @0 M
If the pipe is vertical, The length of heat trace can be installed is about
9 l1 N# O/ A, R0 M1 |: F5 I1 * 10 = 10 meters.
" w: A' U* O) PFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe4 o2 w3 x3 h7 }3 X ?5 M: n
if the pipe is horizontal , The length of heat trace can be installed is about
; ^7 c+ F/ J) n& M1 * 4 = 4 meters
" S/ G# f* Z6 K. s, p6 J+ UIf the pipe is vertical, The length of heat trace can be installed is about
' F* s. P7 J* r( Y% ]4 |1 * 5 = 5 meters. |
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